Persamaan Kuadrat •Part 2: Menyelesaikan Persamaan Kuadrat dengan Pemfaktoran / Faktorisasi Tipe 3&4

Welcome to the science window channel in this video we will discuss the second part of the quadratic equation, which is about solving quadratic equations with type 3 and 4 factorization, keep watching this video until the end. The characteristic of type 3 factorization is a = 1 B does not = 0 c does not

= 0 so all a b c is there only A or the x² coefficient is = 1 so the form becomes x² + BX + c = 0 now how to factor it this form is factored into x + p * x + Q = 0 with p + q = b and p * q = C now

how come P and Q suddenly appear from where I will explain what it means in the example question. What is it like? Okay, let's go straight to the example question to solve the following quadratic equation x² + 5X + 6 = 0 so this is a characteristic of type 3 the x² coefficient is 1 so x²

then B = c there is b 5 c 6 a 1 we factor it like this for type 3 we make brackets X then give a gap give a distance like This is a closing bracket and then an opening bracket X again, give a gap, the closing bracket like this is equal to 0, now this gap or empty space

will be filled with numbers, what numbers are we looking for? Two numbers, if added together, the result is b or 5, and multiplied, the result is c or 6, so if you are confused, just make it like this, scribble, yes, dots plus dots, this is equal to b or 5 dots multiplied by dots, this is equal

to C or 6, we are looking for these dots, how many are the two numbers, if added together, it is equal to 5, if multiplied = 6, how much is 2 equal to 3 because, for example, 2 + 3 is 5, 2 * 3 is 6, now 2 and 3 are P and Q, so here